3x^2-5xy^2+2y^4=0

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Solution for 3x^2-5xy^2+2y^4=0 equation:


Simplifying
3x2 + -5xy2 + 2y4 = 0

Reorder the terms:
-5xy2 + 3x2 + 2y4 = 0

Solving
-5xy2 + 3x2 + 2y4 = 0

Solving for variable 'x'.

Factor a trinomial.
(x + -1y2)(3x + -2y2) = 0

Subproblem 1

Set the factor '(x + -1y2)' equal to zero and attempt to solve: Simplifying x + -1y2 = 0 Solving x + -1y2 = 0 Move all terms containing x to the left, all other terms to the right. Add 'y2' to each side of the equation. x + -1y2 + y2 = 0 + y2 Combine like terms: -1y2 + y2 = 0 x + 0 = 0 + y2 x = 0 + y2 Remove the zero: x = y2 Simplifying x = y2

Subproblem 2

Set the factor '(3x + -2y2)' equal to zero and attempt to solve: Simplifying 3x + -2y2 = 0 Solving 3x + -2y2 = 0 Move all terms containing x to the left, all other terms to the right. Add '2y2' to each side of the equation. 3x + -2y2 + 2y2 = 0 + 2y2 Combine like terms: -2y2 + 2y2 = 0 3x + 0 = 0 + 2y2 3x = 0 + 2y2 Remove the zero: 3x = 2y2 Divide each side by '3'. x = 0.6666666667y2 Simplifying x = 0.6666666667y2

Solution

x = {y2, 0.6666666667y2}

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